Consider Array (1 2 3) , Below are the Sub-Array for this Array and their sum.

(1): Sum of this sub-array is 1

(2): Sum of this sub-array is 2

(3): Sum of this sub-array is 3

(1 2): Sum of this sub-array is 3

(2 3): Sum of this sub-array is 5

(1 2 3): Sum of this sub-array is 6

So, there are 6 Sub Array in this Particular Array.

Now, we need to find out sum of all these Array using shell scripting.

NOTE : *You can remove the outer most while loop and just pass the value of k where k is the length of Sub Array in order to find Sum of Sub Array having length N(which is K here in our case)*.

`arr=(1 2 3) ## `

*Array of 3 elements*

len1=${#arr[@]} ## *Length of Array arr*

SumSubArr=()## *created Empty Array*

LenOfSubArr=1 ## *Minimum length of Sub Array is 1*.

while [ $LenOfSubArr -le $len1 ]

do

k=$LenOfSubArr

j=0

i=0

k1=$(( $k - 1))

k2=$k

loopLen=$(($len1 - $k2 + 1))

while [ $i -lt $loopLen ] ## *This will run for all Sub Array of Particular Length using Variable LenOfSubArr*.

do

sum_arr=0

while [ $j -lt $k ] ## *This loop will sum values of all elements present in each Sub Array*

do

sum_arr=$(($sum_arr + ${arr[j]}))

j=$(( $j + 1))

done

SumSubArr+=$sum_arr

i=$(( $i + 1))

j=$(( $j - $k1))

k=$(( $k + 1))

done

LenOfSubArr=$(( $LenOfSubArr +1))

done

echo ${SumSubArr[*]}